Article
Kyungpook Mathematical Journal 2017; 57(1): 133-144
Published online March 23, 2017 https://doi.org/10.5666/KMJ.2017.57.1.133
Copyright © Kyungpook Mathematical Journal.
On the Ruled Surfaces with L 1-Pointwise 1-Type Gauss Map
Young Ho Kim1
Nurettìn Cenk Turgay2
Department of Mathematics, Kyungpook National University, Daegu 41566, Korea1
Department of Mathematics, Istanbul Technical University, 34469 Maslak, Istanbul, Turkey2
Received: June 18, 2014; Accepted: October 17, 2014
Abstract
In this paper, we study ruled surfaces in 3-dimensional Euclidean and Minkowski space in terms of their Gauss map. We obtain classification theorems for these type of surfaces whose Gauss map
Keywords: Cheng-Yau operator, Gauss map, null scroll, pointwise 1-type, ruled surface
1. Introduction
Let
On the other hand, if the Gauss map
for a constant λ ∈ ℝ and a constant vector
for some function
In the recent years, the definition of being
In [15], the authors give the following definition.
Definition 1. ([15])
An oriented surface
for a smooth function
In the same paper, authors states
Open Problem
Classify surfaces in with □-1-type Gauss map.
On the other hand, there are many studies done on rotational surfaces, ruled surfaces and translation surfaces in terms of being finite type or having pointwise 1-type Gauss map. For example, in [5] and [14], the rotational surfaces of the Euclidean 3-space and the Minkowski 3-space
In this paper, we study rotational surfaces, ruled surfaces and translation surfaces in and
2. Prelimineries
Let
A non-zero vector
On the other hand, a two dimensional subspace
The following lemmas are well-known and useful (see, for instance [13]):
Lemma 2.1
Lemma 2.2
Lemma 2.3
2.1. Surfaces in 3-dimensional Euclidean and Minkowski spaces
Let
Then, we have 〈
The well-known Gauss and Weingarten formulas are given by
for tangent vector fields
Then, the Codazzi equation is given by
for tangent vector fields
The functions ,
The Gauss equation is given by
where
We will use
2.2. Surfaces with □-pointwise 1-type Gauss map
Let
for
We will use following lemma and theorems in [15].
Lemma 2.4. ([15])
Theorem 2.5. ([15])
Theorem 2.6. ([15])
Theorem 2.7. ([15])
3. Ruled Surfaces in
Let
Because of these assumptions, we have
and
for some smooth functions
We choose an orthonormal frame field as
where
By a direct calculation, we obtain the connection form
where {
where
On the other hand, from the Codazzi
By using (
3.1. Ruled surfaces with □-pointwise 1-type Gauss map of the first kind
We first give the following theorem:
M has □-pointwise 1-type Gauss map of the first kind. M has □-harmonic Gauss map. α ′ =a β ′for a smooth function a.
⇔ (2):
K t = 0 impliesKw = 0 because of (3.12 ). Thus, ifK t = 0 andK ≠ 0 at a pointp ofM, then there exists a neighborhood ofp such that = 0 which is not possible because of (3.4 ). Therefore, we have ifK is constant, thenK = 0. Hence, from Theorem 2.5 and Theorem 2.6 we obtain (1) ⇔ (2).⇔ (3): Because of (
3.5 ) and (3.8 ),M is flat if and only ifb ≡ 0 which is equivalent toα ′ =a β ′ because of (3.1 ).
3.2. Ruled surfaces with □-pointwise 1-type Gauss map of the second kind
Theorem 3.2
Let
Note that from (
On the other hand, by using Gauss and Weingarten formulas, we obtain
Thus, ∇∂
Now, we assume towards a contradiction that
on ℳ. By taking derivative of this equation and using (
on ℳ. Next, we multiply both sides of this equation by
By using (
on ℳ, from which, we obtain
Note that if
From (
The converse is obvious.
3.3. Ruled surfaces with □G = AG for a matrix A ∈ ℝ3x 3
In this section, we suppose that
By taking covariant derivative of this equation on the direction
as ∇
Note that, by using (
From this equation and (
which implies
Theorem 3.3
Combining Theorem 3.2 and Theorem 3.3, we obtain
Theorem 3.4
M has □-pointwise 1-type Gauss map of the second kind. The Gauss map G of M satisfies □G =AG for a matrix A ∈ ℝ3x 3.M is flat.
4. Null scrolls in E 1 3
A non-degenerate ruled surface
On the other hand, if 〈
The tangent vector fields
for a non-vanishing function
4.1. Gauss map of null scrolls
In the next lemma, we obtain □
Let
By considering (
By using this equation and (
Thus, we have (
Example 1
If
because of (
Next, we want to give classification of null scrolls in
Proposition 4.2
Let
for a constant vector
Now, we consider the open subset ℳ = {
on ℳ. By a further calculation taking into account of Gauss formula (
By combining (
The converse is given in Example 1.
Now, we obtain the following proposition.
Proposition 4.3
Suppose the the Gauss map
from which, we get
By using (
from which we get
By combining this equation with (
The converse is given in Example 1.
By combining Proposition 4.2 and Proposition 4.3 with the result of [1], we obtain the following theorem.
Theorem 4.4
M has □-pointwise 1-type Gauss map. The Gauss map G of M satisfies ΔG =AG for a constant 3× 3-matrix A. The Gauss map G of M satisfies □G =AG for a constant 3× 3-matrix A. M is a B-scroll.
Acknowledgements
This work was done while the second named author was visiting Kyungpook National University, Korea between February and August in 2012.
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