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Kyungpook Mathematical Journal 2020; 60(1): 133-144

Published online March 31, 2020

Copyright © Kyungpook Mathematical Journal.

Generalized Hyers-Ulam Stability of Some Cubic-quadraticadditive Type Functional Equations

Yang-Hi Lee, Soon-Mo Jung∗

Department of Mathematics Education, Gongju National University of Education, Gongju 32553, Republic of Korea
e-mail : yanghi2@hanmail.net
Mathematics Section, College of Science and Technology, Hongik University, Sejong 30016, Republic of Korea
e-mail : smjung@hongik.ac.kr

Received: August 8, 2019; Revised: January 11, 2020; Accepted: February 10, 2020

We will prove the generalized Hyers-Ulam stability of cubic-quadratic-additive type functional equations and general cubic functional equations whose solutions are cubic-quadratic-additive mappings and general cubic mappings, respectively.

Keywords: generalized Hyers-Ulam stability, functional equation, cubicquadratic-additive mapping.

Throughout this paper, we assume that V and W are real vector spaces and k is a real number satisfying k ∉ {−1, 0, 1} unless there are specifications for them. For any given mapping f : VW, we will set

D1f(x,y)=f(x+ky)-k2+k2f(x+y)+(k2-1)f(x)-k2-k2f(x-y)-f(ky)+k2+k2f(y)+k2-k2f(-y),D2f(x,y)=f(x+2y)-f(x-2y)-2f(x+y)+2f(x-y)+6f(y)+2f(-y)-2f(2y),D3f(x,y)=f(x+ky)+f(x-ky)-k2f(x+y)-k2f(x-y)+2(k2-1)f(x),D4f(x,y)=f(x+3y)-5f(x+2y)+10f(x+y)-10f(x)+5f(x-y)-f(x-2y)+4f(y)+4f(-y)-f(2y)-f(-2y),D5f(x,y)=f(x+2y)-f(x-2y)-2f(x+y)+2f(x-y)-2f(3y)+6f(2y)-6f(y),D6f(x,y,z)=f(x+y+z)+f(x-y-z)+f(x-y+z)+f(x+y-z)-2f(x+y)-2f(x-y)-2f(x+z)-2f(x-z)+4f(x),D7f(x,y,z)=f(x+y+z)-f(x-y-z)-f(x+y)+f(x-y)-f(x+z)+f(x-z)-f(y+z)+f(-y-z)+f(y)-f(-y)+f(z)-f(-z)

for all x, y, zV.

Every solution of functional equation

i=01(-1)1-iC1if(x+iy)-f(y)=0

is called an additive mapping, and each solution of functional equation

i=02(-1)2-iC2if(x+iy)-2!f(y)=0

is called a quadratic mapping, while every solution of functional equation

i=03(-1)3-iC3if(x+iy)-3!f(y)=0

is called a cubic mapping.

If a mapping can be expressed by the sum of an additive mapping, a quadratic mapping, and a cubic mapping, then we call the mapping a cubic-quadratic-additive mapping. If a mapping can be expressed by the sum of a constant, an additive mapping, a quadratic mapping, and a cubic mapping, then we call the mapping a general cubic mapping. A functional equation is called a cubic-quadratic-additive type functional equation if each solution of that equation is a cubic-quadratic-additive mapping. A functional equation is called a general cubic type functional equation when each of its solutions is a general cubic mapping.

In 1940, Ulam [13] raised an important problem concerning the stability of group homomorphisms: Under what conditions is the approximate solution of an equation necessarily close to the exact solution of the equation? Just the following year, Hyers [8] solved the problem of Ulam only in the case of the Cauchy additive functional equation Af(x, y) = f(x + y) − f(x) − f(y) = 0. Indeed, Hyers proved the following statement for any previously given constant ɛ > 0: every solution of inequality ||Af(x, y)|| ≤ ɛ (for all x and y) can be approximated by an exact solution (an additive function). In this case, the Cauchy additive functional equation is said to satisfy the Hyers-Ulam stability.

About three decades later, Rassias [12] generalized Hyers’ result and then Găvruta [7] extended Rassias’ result by allowing unbounded control functions. The concept of stability introduced by Rassias and Găvruta is known today as the generalized Hyers-Ulam stability of functional equations.

Jun et al. [9] and Lee [10] investigated the stability of the general cubic functional equation D3f(x, y) = 0 for k = 2. Independently from them, Gordji [3] investigated the stability of the cubic-quadratic-additive functional equation D5f(x, y) = 0. Moreover, Gordji et al. [2, 3, 4, 5, 6] investigated the stability of the general cubic functional equation D3f(x, y) = 0 for any integer k ∉ {−1, 0, 1}. However, they could not prove the uniqueness of the exact solution because they divided the related function into even and odd parts and proved their stability separately, while we prove in this paper the stability in an integrated way. At the same time, we prove the uniqueness of the exact solution. This is an advantage of this paper in comparison with the papers [2, 3, 4, 5, 6] of other mathematicians.

In this paper, we will prove the generalized Hyers-Ulam stability of the functional equations Dmf(x, y) = 0 for m ∈ {1, 2, 3, 4, 5} and Dmf(x, y, z) = 0 for m ∈ {6, 7}.

The following theorem is a special version of Baker’s theorem when δ = 0 (refer to [1]).

Theorem 2.1. ([1, Theorem 1])

Given an m ∈ ℕ, assume that V and W are vector spaces over ℚ, ℝ orand that α0, β0, . . . , αm, βm are scalars satisfying αjβαβj ≠ 0 whenever 0 ≤ j < m. If the functions f : VW, ℓ ∈ {0, 1, . . . , m}, satisfy the equation

=0mf(αx+βy)=0

for all x, yV, then each f is a generalized polynomial mapping of degree at most m − 1.

Baker [1] also states that if f : VW is a generalized polynomial mapping of degree at most m − 1, then f can be expressed as f(x)=x0+=1m-1a*(x) for xV, where a* is a monomial mapping of degree and f has a property f(rx)=x0+=1m-1ra*(x) for xV and r ∈ ℚ. The monomial mapping of degree 1, 2 and 3 are called an additive mapping, a quadric mapping, and a cubic mapping, respectively. The generalized polynomial mapping of degree 1, 2 and 3, on the other hand, are called a Jensen mapping, a general quadric mapping, and a general cubic mapping, respectively.

In summary, the following corollary can be obtained from Baker’s theorem.

Corollary 2.2

Let V and W be vector spaces over ℚ, ℝ or ℂ, and let r be a rational number satisfying r ∉ {−1, 0, 1}. Given an m ∈ ℕ, assume that n1, . . . , nm are positive integers and that cℓ,i, dℓ,i, α0, β0, . . . , αm, βm ( ∈ {1, . . . , m} and i ∈ {1, . . . , n}) are scalars satisfying αjβαβj ≠ 0 whenever 0 ≤ j < m. If a mapping f : VW satisfies the equation f(rx) = rkf(x) for all xV and the equation

f(α0x+β0y)+=1mi=1nc,if(d,i(αx+βy))=0

for all x, yV, then f is a monomial mapping of degree k.

Proof

Put

f0(α0x+β0y)=f(α0x+β0y)

and

f(αx+βy)=i=1nc,if(d,i(αx+βy))

for all ∈ {1, . . . , m}. Then f0, . . . , fm satisfy the conditions of Theorem 2.1. So f is a generalized polynomial mapping of degree at most m − 1. In addition, since f satisfies the equation f(rx) = rkf(x) for all xV, f is a monomial mapping of degree k.

According to Theorem 2.1, the functional equations D1f(x, y) = 0, D2f(x, y) = 0, D4f(x, y) = 0, D5f(x, y) = 0, D6f(x, y, y) = 0, and D7f(x, y, y) = 0 are cubic-quadratic-additive type functional equations, and the functional equation D3f(x, y) = 0 is a general cubic type functional equation. Since D6f(x, y, y) = 0 and D7f(x, y, y) = 0 are cubic-quadratic-additive type functional equations, D6f(x, y, z) = 0 and D7f(x, y, z) = 0 are cubic-quadratic-additive type functional equations.

Hereafter, let Y be a real Banach space. For any mapping f : VY and any function ϕ : V × V → [0,∞), we use the following notations:

fe(x)=f(x)+f(-x)2,fo(x)=f(x)-f(-x)2,ϕe(x,y)=ϕ(x,y)+ϕ(-x,-y)2.

Lemma 2.3

Let V be a real vector space and let (Y, || · ||) be a real Banach space. Given an m ∈ {1, 2, 3, 4, 5}, assume that a mapping f : VY satisfies f(0) = 0 and inequality

Dmf(x,y)ϕ(x,y)

for all x, yV. Then the following inequalities

fe(2x)-4fe(x)μm(x),fo(4x)-10fo(2x)+16fo(x)νm(x)

hold for all xV, where μm, νm : V → ℝ are defined by

μ1(x):=14k3-4k××(k-2(ϕe(x,2x)+ϕe((k+1)x,x)+k2+k2ϕe(2x,x))+k+2(ϕe(x,-2x)+ϕe((k-1)x,x)+k2-k2ϕe(-2x,x))+4ϕe(kx,x)+2k3+k2-k-2ϕe(-x,x)+k3-4k2-3k+2ϕe(x,x)),μ2(x):=12ϕe(0,x),μ3(x):=1k4-k2××(ϕe(kx,x)+k2ϕe(x,x)+12ϕe(0,2x)+k2-1ϕe(0,x)),μ4(x):=14(ϕe(0,x)+ϕe(-x,x)),         μ5(x):=110(ϕe(-x,x)+3ϕe(0,x)),ν1(x):=1k4-k2k+2××((k+2)(2ϕe((k-2)x,x)+2ϕe((k+2)x,x)+2ϕe(2x,2x)-2ϕe(-2x,2x)-(k2+k)ϕe(3x,x)+k2-kϕe(-3x,x)+2k2-1ϕe(-2x,x))+16ϕe(x,2x)+16ϕe(kx,x)+16ϕe((k+1)x,x)+2k3-2k2-k-6ϕe(2x,x)+k3+11k2-6kϕe(-x,x)+k3-23k2-10k-16ϕe(x,x)),ν2(x):=ϕe(2x,x)+2ϕe(x,x),ν3(x):=1k4-k2××(4k2-3ϕe(x,x)+2k2ϕe(2x,x)+2k2ϕe(x,2x)+2ϕe((k+1)x,x)+2ϕe((k-1)x,x)+k2ϕe(2x,2x)+ϕe(x,3x)+ϕe((2k+1)x,x)+ϕe((2k-1)x,x)),ν4(x):=ϕe(x,x)+5ϕe(0,x),         ν5(x):=ϕe(2x,x)+2ϕe(0,x).
Proof

Some somewhat long and tedious calculations yield the following equalities:

fe(2x)-22fe(x)=14k3-4k((k-2)(D1fe(x,2x)-D1fe((k+1)x,x)-k2+k2D1fe(2x,x))-(k+2)(D1fe(x,-2x)-D1fe((k-1)x,x)-k2-k2D1fe(-2x,x))-4D1fe(kx,x)+(2k3+k2-k-2)D1fe(-x,x)+(k3-4k2-3k+2)D1fe(x,x))=-D2fe(0,x)2=D3fe(kx,x)+k2D3fe(x,x)-12D3fe(0,2x)-(k2-1)D3fe(0,x)k4-k2=D4fe(0,x)+D4fe(-x,x)4=3D5fe(0,x)-2D5fe(-x,x)10fo(4x)-10fo(2x)+16fo(x)=1(k4-k2)(k+2)((k+2)(2D1fo((k-2)x,x)-2D1fo((k+2)x,x)+2D1fo(2x,2x)-2D1fo(-2x,2x)-(k2+k)D1fo(3x,x)+(k2-k)D1fo(-3x,x)-2(k2-1)D1fo(-2x,x))+16D1fo(x,2x)+16D1fo(kx,x)-16D1fo((k+1)x,x)+2(k3-2k2-k-6)D1fo(2x,x)+(k3+11k2-6k)D1fo(-x,x)-(k3-23k2-10k-16)D1fo(x,x))=D2fo(2x,x)+2D2fo(x,x)=1k4-k2((4k2-3)D3fo(x,x)-2k2D3fo(2x,x)+2k2D3fo(x,2x)-2D3fo((k+1)x,x)+2D3fo((k-1)x,x)-k2D3fo(2x,2x)+D3fo(x,3x)-D3fo((2k+1)x,x)+D3fo((2k-1)x,x))=D4fo(x,x)+5D4fo(0,x)

and

fo(4x)-10fo(2x)+16fo(x)=D5fo(2x,x)-2D5fo(0,x)

for all xV. Thus, we can easily obtain the inequalities in (2.2).

Recall that Y is a real Banach space.

Lemma 2.4

Given m ∈ {1, 2, 3, 4, 5}, assume that a mapping f : VY satisfies f(0) = 0 and Dmf(x, y) = 0 for all x, yV. Then the equalities

f1(2x)=2f1(x),         f2(2x)=4fe(x),         f3(2x)=8f3(x)

are true for all xV, where

fo(x):=f(x)-f(-x)2,      fe(x):=f(x)+f(-x)2,f1(x):=8fo(x)-fo(2x)6,      f3(x):=-2fo(x)-fo(2x)6.
Proof

According to inequalities of (2.2), we obtain the equalities

fe(2x)-4fe(x)=0         and         fo(4x)-10fo(2x)+16fo(x)=0

for all xV. We can easily derive equalities of (2.4) from the last equalities.

Using [11, Theorems 4.1–4.4] for the case of a = 2 and n = 2, we can prove the following theorems.

Theorem 2.5

Let m ∈ {1, 2, 3, 4, 5} be fixed and let ϕ : V × V → [0,∞) be a function satisfying the condition

i=0ϕ(2ix,2iy)2i<

for all x, yV. If a mapping f : VY satisfies f(0) = 0 and inequality(2.1)for all x, yV, then there exists a unique mapping F : VY satisfying

DmF(x,y)=0

for all x, yV and

f(x)-F(x)i=0(μm(2ix)4i+1+(4i+1-1)νm(2ix)6·8i+1)

for all xV.

Proof

On account of Lemma 2.3, the following inequalities

fe(2x)-4fe(x)μm(x)         and         fo(4x)-10fo(2x)+16fo(x)νm(x)

hold for all xV. Due to [11, Theorems 3.1], there exists a unique mapping F : VY satisfying equality (2.6) for all x, yV, inequality (2.7) for all xV, and equalities of (2.4) for all xV. Since equalities of (2.4) can be derived from (2.6), we conclude that there exists a unique mapping F : VY satisfying equality (2.6) for all x, yV and inequality (2.7) for all xV.

Theorem 2.6

Let m ∈ {1, 2, 3, 4, 5} be fixed and let ϕ : V × V → [0,∞) be a function satisfying the condition

i=08iϕ(x2i,y2i)<

for all x, yV. If a mapping f : VY satisfies f(0) = 0 and inequality(2.1)for all x, yV, then there exists a unique mapping F : VY satisfying equality(2.6)for all x, yV and

f(x)-F(x)i=0(4iμm(x2i+1)+8i+1-2i+16νm(x2i+2))

for all xV.

Proof

By Lemma 2.3, we obtain

fe(2x)-4fe(x)μm(x)         and         fo(4x)-10fo(2x)+16fo(x)νm(x)

for all xV. By [11, Theorems 3.2], there exists a unique mapping F : VY satisfying equality (2.6) for all x, yV and inequality (2.9) for all xV.

Theorem 2.7

Let m ∈ {1, 2, 3, 4, 5} be fixed and let ϕ : V × V → [0,∞) be a function satisfying the conditions

i=0ϕ(2ix,2iy)4i<         and         i=02iϕ(x2i,y2i)<

for all x, yV. If a mapping f : VY satisfies f(0) = 0 and inequality(2.1)for all x, yV, then there exists a unique mapping F : VY satisfying equality(2.6)for all x, yV and

f(x)-F(x)i=0μm(2ix)4i+1+16i=0(νm(2ix)8i+1+2iνm(x2i+1))

for all xV.

Proof

Using Lemma 2.3, we have

fe(2x)-4fe(x)μm(x)         and         fo(4x)-10fo(2x)+16fo(x)νm(x)

for all xV. On account of [11, Theorems 3.3], there exists a unique mapping F : VY satisfying equality (2.6) for all x, yV and inequality (2.11) for all xV.

Recall that Y is a real Banach space.

Theorem 2.8

Let m ∈ {1, 2, 3, 4, 5} be fixed and let ϕ : V × V → [0,∞) be a function satisfying the conditions

i=0ϕ(2ix,2iy)8i<         and         i=04iϕ(x2i,y2i)<

for all x, yV. If a mapping f : VY satisfies f(0) = 0 and inequality(2.1)for all x, yV, then there exists a unique mapping F : VY satisfying equality(2.6)for all x, yV as well as inequality

f(x)-F(x)i=0(4iμm(x2i+1)+16(νm(2ix)8i+1+2iνm(x2i+1)))

for all xV.

Proof

In view of Lemma 2.3, the following inequalities

fe(2x)-4fe(x)μm(x)         and         fo(4x)-10fo(2x)+16fo(x)νm(x)

hold for all xV. Due to [11, Theorems 3.4], there exists a unique mapping F : VY satisfying equality (2.6) for any x, yV and inequality (2.11) for each xV.

Lemma 2.9

Given an m ∈ {6, 7} and a function ϕ : V3 → [0,∞), assume that a mapping f : VY satisfies f(0) = 0 and

Dmf(x,y,z)ϕ(x,y,z)

for all x, y, zV. Then inequalities of(2.2)are true for all xV, where μm, νm : V → ℝ are defined by

μ6(x):=2ϕe(0,x,x)2,ν6(x):=ϕe(2x,x,x)+4ϕe(x,x,x),μ7(x):=ϕe(x,x2,x2)+2ϕe(x2,x2,x2),ν7(x):=ϕe(2x,x,x)+2ϕe(x,x,x)

for all xV.

Proof

Since the equalities

fe(2x)-22fe(x)=D6fe(0,x,x)2=D7fe(x,x2,x2)+2D7fe(x2,x2,x2)

and

fo(4x)-10fo(2x)+16fo(x)=D6fo(2x,x,x)+4D6fo(x,x,x)=D7fo(2x,x,x)+2D7fo(x,x,x)

are true for any xV, we can easily obtain inequalities in (2.2).

Lemma 2.10

Given an m ∈ {6, 7} and a function ϕ : V3 → [0,∞), assume that a mapping f : VY satisfies f(0) = 0 and Dmf(x, y, z) = 0 for all x, y, zV. Then equalities in(2.4)are true for all xV.

Proof

Due to inequalities of (2.2), we get

fe(2x)-4fe(x)=0         and         fo(4x)-10fo(2x)+16fo(x)=0

for any xV.

Hence, we can derive equalities of (2.4) from the above equalities.

By applying [11, Theorems 4.1–4.4] for the case of a = 2 and n = 3, we can prove the following theorems.

Theorem 2.11

Let m ∈ {6, 7} be fixed and let ϕ : V3 → [0,∞) be a function satisfying the condition

i=0ϕ(2ix,2iy,2iz)2i<

for all x, y, zV. If a mapping f : VY satisfies f(0) = 0 and inequality(2.14)for all x, y, zV, then there exists a unique mapping F : VY satisfying

DmF(x,y,z)=0

for all x, y, zV as well as inequality(2.7)for all xV.

Again, Y is a real Banach space.

Theorem 2.12

Let m ∈ {6, 7} be fixed and let ϕ : V3 → [0,∞) be a function satisfying the condition

i=08iϕ(x2i,y2i,z2i)<

for all x, y, zV. If a mapping f : VY satisfies f(0) = 0 and inequality(2.14)for all x, y, zV, then there exists a unique mapping F : VY satisfying equality(2.16)for all x, y, zV and inequality(2.9)for all xV.

Theorem 2.13

Let m ∈ {6, 7} be fixed and let ϕ : V3 → [0,∞) be a function satisfying the conditions

i=0ϕ(2ix,2iy,2iz)4i<         and         i=02iϕ(x2i,y2i,z2i)<

for all x, y, zV. If a mapping f : VY satisfies f(0) = 0 and inequality(2.14)for all x, y, zV, then there exists a unique mapping F : VY satisfying equality(2.16)for all x, y, zV and inequality(2.11)for all xV.

Theorem 2.14

Let m ∈ {6, 7} be fixed and let ϕ : V3 → [0,∞) be a function satisfying the conditions

i=0ϕ(2ix,2iy,2iz)8i<         and         i=04iϕ(x2i,y2i,z2i)<

for all x, y, zV. If a mapping f : VY satisfies f(0) = 0 and inequality(2.14)for all x, y, zV, then there exists a unique mapping F : VY satisfying equality(2.16)for all x, yV and inequality(2.13)for all xV.

Subjects similar to those covered in this paper have been studied previously (see [3, 5, 6, 4, 2]). However, in these works, the proof of the uniqueness of the exact solution was not possible, because the stability of the related functions was proved separately for the even and odd parts. We feel that the uniqueness of the solution is important, and that the division into even and odd parts is somewhat unnatural.

In this paper, we were able to prove the stability of the related function in an integrated way, without dividing the related function into even and odd parts. This allows us to prove the uniqueness of the exact solution. We see this a significant improvement over the results of [3, 5, 6, 4, 2].

Because of space constraints, let us look at only one example that uses the results of this paper. If we put m = 7, n = 2, c1 = 1, c2 = −1, c3 = −2, c4 = 2, c5 = 6, c6 = 2, c7 = −2, a11 = 1, a12 = 2, a21 = 1, a22 = −2, a31 = 1, a32 = 1, a41 = 1, a42 = −1, a51 = 0, a52 = 1, a61 = 0, a62 = −1, a71 = 0, a72 = 2 in (1.1) in [11], then the expression (1.1) in [11] becomes D2f(x, y) in this paper. We have proved the (generalized) Hyers-Ulam stability of the functional equation D2f(x, y) = 0 in Theorem 2.5 of this paper. If we set ϕ(x, y) = ɛ > 0, then it follows from Theorem 2.5 that there exists a unique function F : VY satisfying D2f(x, y) = 0 for all x, yV and

f(x)-F(x)i=0(μ2(2ix)4i+1+(4i+1-1)ν2(2ix)6·8i+1)=2542ɛ

for all xV. In the text of Lemma 2.3, we can see the definitions of μ2 and ν2.

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